2014-06-16から1日間の記事一覧

二つの変数によるガウス確率分布の続き

In fact, it is easier to solve for the general multivariate Gaussian and then substitute for x with n=2. For x as am n-dimensional vector of independent normal random variables with mean 0 and variance 1, f(x) = (1/(2pi))^(n/2)e^*1. By the…